๐Ÿฆ˜ Oblicz 1 1 3 X 2 5

Algebra. Solve for x 1/5-x/5=-2/5. 1 5 โˆ’ x 5 = โˆ’ 2 5 1 5 - x 5 = - 2 5. Move all terms not containing x x to the right side of the equation. Tap for more steps โˆ’ x 5 = โˆ’3 5 - x 5 = - 3 5. Since the expression on each side of the equation has the same denominator, the numerators must be equal. โˆ’x = โˆ’3 - x = - 3. Divide 9, the coefficient of the x term, by 2 to get \frac{9}{2}. Then add the square of \frac{9}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square. First, distribute. Explanation: 12xโˆ’48โˆ’xโˆ’2 = x2 +2xโˆ’4xโˆ’8 0 = x2 โˆ’13x+40 0 =(xโˆ’8)(xโˆ’5) (2x-1) (x-4)= (x-6) (2x-3) One solution was found : x = 7/3 = 2.333 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the 3 (x+2)+2 (x-4)=x-3 (x+3) One solution was found : x = -1 Step 1.3.2. Multiply by . Step 1.3.3. Reorder the factors of . Step 1.4. Combine the numerators over the common denominator. Step 1.5. Rewrite in a factored form. x= โˆ’3 Explanation: 3(x+5)= 2(3x+12) or 3โ‹…x+15 = 6โ‹…x+24 or 3โ‹…xโˆ’6โ‹…x = 24โˆ’15 or โˆ’3โ‹…x= 9 2x+9+3x+x=1x+5 One solution was found : x = -4/5 = -0.800 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation 3x+15=3 (x+5) Equation is alway true Rearrange: Rearrange Step 1 : 1 Simplify โ€” 3 Equation at the end of step 1 : 1 (โ€” โ€ข (x - 2)) - 5 = 0 3 Step 2 : Equation at the end of step 2 : (x - 2) โ€”โ€”โ€”โ€”โ€”โ€”โ€” - 5 = 0 3 Step 3 : Rewriting the whole as an Equivalent Fraction : 3.1 Subtracting a whole from a fraction Oct 3, 2014 ยท 64. A train running at a uniform speed of 75 km/hr. How much time will it take to cover a distance of 350 km? a. 4 hours c. 4 hrs. 30 min b. 5 hours. ananya bought a piece of jewellery for rs 1550 and sold it for rs 1600 find the gain per cent . What is 81% of =40.5. Advertisement. 1/2x-3 +1/x-5 =1 solve for x Get the answers you need, now! Click here:point_up_2:to get an answer to your question :writing_hand:integrate the functioncfracmathbfxsqrtmathbfx4 mathbfx0 3 / 8 + 2 / 8 = 5 / 8 + = Three-eighths plus two-eighths equals five-eighths There are two popular methods to make the denominators the same: Least Common Denominator There are other sets of polar coordinates that will be the same as our first solution. For example, the points (โˆ’ 3 2, 5 ฯ€ 4) (โˆ’ 3 2, 5 ฯ€ 4) and (3 2, โˆ’ 7 ฯ€ 4) (3 2, โˆ’ 7 ฯ€ 4) will coincide with the original solution of (3 2, ฯ€ 4). (3 2, ฯ€ 4). The point (โˆ’ 3 2, 5 ฯ€ 4) (โˆ’ 3 2, 5 ฯ€ 4) indicates a move further counterclockwise Solve each of the following quadratic equations:(i) 1 xโˆ’1โˆ’ 1 x+5 = 6 7,xโ‰ 1,โˆ’5(ii) 1 2xโˆ’3โˆ’ 1 xโˆ’5=11 9,xโ‰  3 2,5. Q. Solve the following: 2x โˆ’ 13 5 โˆ’ x โˆ’ 3 11 = x โˆ’ 9 5 + 1. Q. Solve the following equation: 2xโˆ’13 5 โˆ’ xโˆ’3 11 = xโˆ’9 5 +1. Q. Solve the following equation: (5 3)x+1 โ‹…( 9 25)x2+2xโˆ’11 =(5 3)9. View More. Question: In the following exercises, use the expansion (1+x)^ (1/3) = 1+ (1/3)x- (1/9)x^2+ (5/81)x^3- (10/243)x^4+ โ‹ฏ to write the first five terms (not necessarily a quartic polynomial) of each expression. (1+4x)^ (4/3) ; a=0. In the following exercises, use the expansion (1+x)^ (1/3) = 1+ (1/3)x- (1/9)x^2+ (5/81)x^3- (10/243)x^4+ โ‹ฏ to uphoP.

oblicz 1 1 3 x 2 5